- Our college team is going to the sports fest to play a football match with our coach. There are n players in our team, numbered from 1 to n.
- The coach will know the position of another team hence creating a winning strategy. He creates the position of every player in a specific order so that we will win and then he starts swapping two players at a time to form the positions.
- He swaps payers in such a way that it can’t be understood by another team:
- Any player can swap with the player directly in front of him
- One player can swap at most with two other players

If the specific order is formed then our team will win otherwise we will lose

**Input Format**

- The First line contains the numbers of players in the team:
- The second line contains n space-separated integers denoting the specific position of players: i-th integer denotes the position of Ai player in the winning strategy

**Output Format**

- If our team wins print “YES”(without quotes) and in the next line print the minimum numbers of swapping required to form this specific order otherwise print “NO”(without quotes)

**Constraints:**

1 =< n <= 10^5

1 <= Ai <= n

**Sample Input1:**

5 2 1 5 3 4

**Sample Output1:**

YES 3

**Sample Input2:**

5 2 5 1 3 4

**Sample Output3:**

NO

**Explanation:**

In the First Sample case,

Initial state: 1 2 3 4 5

Three moves are required to form this order:

1 2 3 4 5 -> 1 2 3 5 4 -> 1 2 5 3 4 -> 2 1 5 3 4

In the second case, no way to form this specific order

**Code:**

```
#include<iostream>
using namespace std;
void printer(int *arr, int n)
{
for(int i=0; i<n; i++)
{
cout << arr[i] << " ";
}
}
int main()
{
int n;
cin >> n;
int* arr = new int[n];
for(int i=0; i<n; i++)
{
cin >> arr[i];
}
int count = 0;
for(int i=n-1; i>=2; i--)
{
if(arr[i]==i+1)
{
continue;
}
else
{
if(arr[i-1]==i+1)
{
count += 1;
int temp = arr[i];
arr[i] = arr[i - 1];
arr[i - 1] = temp;
}
else if(arr[i-2]==i+1)
{
count += 2;
arr[i - 2] = arr[i - 1];
arr[i - 1] = arr[i];
arr[i] = i + 1;
}
else
{
cout << "NO";
return 0;
}
}
}
if(arr[0]==2 && arr[1]==1)
{
arr[0] = 1;
arr[1] = 2;
count += 1;
cout << "YES" << endl << count;
}
else if(arr[0]==1 && arr[1]==2)
{
cout << "YES" << endl << count;
}
else
{
cout << "NO";
}
}
```

Code language: C++ (cpp)