CPP Program Circular List of Students – Adhoc Problems

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You are given a circular list of students as follows:

0 -> 1 -> 2 -> 3 -> 4 -> 5 -> 6 -> 7 -> 8 -> 9 -> 10 -> 11

  • This list is circular, which means that 11 will follow 0 again.
  • You will be given the student number ‘i’ and some position ‘p’.
  • You will have to tell that if the list will start from (i+1)th student, then which student will be at pth position.

Input Format:

  • The first line will have an integer ‘t’, denoting the number of test cases.
  • The next line will have two space-separated integers denoting the value of ‘i’ and ‘p’ respectively.

Output Format:

  • Print ‘t’ lines containing a single integer denoting the student number.

Constraints:

1 <= t <= 10^5 0 <= i <= 11 1 <= p <= 12

Sample Input: 

2 2 3 5 8

Sample Output: 

5 1

Explanation:

  • First, list will start at 3. 3 -> 4 -> 5. Hence, 5 will be at the third position.
  • Second, list will start at 6. 6 -> 7 -> 8 -> 9 -> 10 -> 11 -> 0 -> 1. Hence, 1 will be in the 8th position.

Code:

#include<iostream>
using namespace std;
int calculate(int i, int p)
{
	int current_student = i+1;
	while(p--)
	{
		if(current_student>11)
		{
			current_student = 0;
		}
		current_student++;
	}
	current_student--;
	if(current_student==-1)
	{
		current_student = 11;
	}
	return current_student;
}
int main()
{
	int t;
	cin >> t;
	while (t--)
	{
		int i, p;
		cin >> i >> p;
		cout<<calculate(i, p)<<endl;
	}
}
Code language: C/AL (cal)

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