C Program to convert the array to double its value and replace the next number with 0

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Write a program to convert the array in such a way that double its value and replace the next number with 0 if the current and next element are the same and rearrange the array such that all 0’s shifted to the end. 

For Example:

The given array is: 0 3 3 3 0 0 7 7 0 9
The new array is: 6 3 14 9 0 0 0 0 0 0

Explanation :

  • In the given array the second and third element is equal hence doubling the first 3 and making the next index value 0.
  • The element which is in the third index doesn’t have any match so leave it as it is. finally, move all zeros to the end

Input Format:
The input contains an integer N which is the size of the array and in the next line N elements will be there 

Constraints:
1<=N<=100
1<=arr[i] <=1000

Output Format:
Print the updated array with the space

 Sample Input 1

10
0 3 3 3 0 0 7 7 0 9

Sample Output 1

6 3 14 9 0 0 0 0 0 0

Code:

#include<stdio.h>

int main()
{
    int n;
    int a[100];
    int i=0;
    scanf("%d",&n);
    for(;i<n;i++) scanf("%d",&a[i]);
    for(int j=0;j<n-1;j++)   
    {
        if(a[j] == a[j+1])
        {
            a[j]=2*a[j];
            a[j+1]=0;
        }
    } 

    i=0;
    for(int j=0;j<n;j++)
    {
        if(a[j]!=0) printf("%d ",a[j]);
        else i++;
    }
    for(int j=0;j<i;j++) printf("0 ");
}
Code language: C/AL (cal)

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