**Write a program to arrange the odd digits and even digits in a given number**

**Input Format**

The input contains an integer and option

If option = 0, even digits should come first

If option = 1, odd digits should come first

**Output Format**

Print the number after seggregation

**Constraint**

1<=Input<=10^7

Sample Input 1

67854 0

Sample Output 1

68475

Sample Input 2

12345 1

Sample Output 2

13524

**Code:**

```
#include<stdio.h>
int main()
{
int n,d;
int i=0;
int a[100],odd[100],even[100];
scanf("%d%d",&n,&d);
while(n)
{
a[i++]=n%10;
n=n/10;
}
int k=0,l=0;
for(int j=0;j<i;j++)
{
if(a[j] %2 == 0)
{
even[k++]=a[j];
}
else
odd[l++]=a[j];
}
if(d == 0)
{
for(int j=k-1;j>=0;j--) printf("%d",even[j]);
for(int j=l-1;j>=0;j--) printf("%d",odd[j]);
}
else
{
for(int j=l-1;j>=0;j--) printf("%d",odd[j]);
for(int j=k-1;j>=0;j--) printf("%d",even[j]);
}
}
```

Code language: C/AL (cal)