Use a list comprehension to square each odd number in a list

Question:

  • Use a list comprehension to square each odd number in a list.
  • The list is input by a sequence of comma-separated numbers. Suppose the following input is supplied to the program: 1,2,3,4,5,6,7,8,9 Then, the output should be: 1,3,5,7,9

Hints:

In case of input data being supplied to the question, it should be assumed to be a console input.

Solution:

values = input() numbers = [x for x in values.split(",") if int(x)%2!=0] print(",".join(numbers))
Code language: Python (python)

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