#### Aim:

To write C program for multiplication of two binary numbers.

#### Algorithm:

Step 1: Convert the input into binaries and store it in variable and array

Step 2: Add the variable binaries with array[i] , i++;

Step 3: Add every result by multiply () function

Step 4: Display the last result

Step 5: End

#### Program:

#include<stdio.h> #include <stdlib.h> int long add(int long k,int long h) { int sum[100]; int i=0,temp=0; printf("\n"); while(k!=0||h!=0) { sum[i]=(k%10+h%10+temp)%2; temp=(k%10+h%10+temp)/2; k=k/10; h=h/10; i++; } if(temp!=0) { sum[i]=temp; } int temp1=1,i1; int long sum3=0; i1=i; for(i=0;i<i1;i++) { if(sum[i]==0) { temp1=temp1*10; } else{ sum3=sum3+temp1; temp1=temp1*10; } } return sum3; int x,sum=0,y,a[100],b[100],j=1; int i=0,temp=0; int long long sum1=0; printf("\nENTER THE 2 NO'S :\n"); scanf("%d%d",&x,&y); while(x>0) { a[i]=x%2; x=x/2; if(a[i]==0) { j=j*10; } else{ sum=sum+j; j=j*10; } i++; } j=1; int s=0; int sum4=0; while(y>0) { b[s]=y%2; y=y/2; if(b[s]==0) { j=j*10; } else{ sum4=sum4+j; j=j*10; } s++; } printf("BINARY OF 1ST NUM : %d\n",sum); printf("BINARY OF 2nd NUM : %d\n",sum4); j=s; i=1; sum1=b[0]*sum; s=1; int long sum2; while(s<j) { i=i*10; sum2=b[s]*sum*i; add(sum1,sum2); sum1=add(sum1,sum2); s++; } printf("MULTIPLY OF 2 NO'S :"); printf("%ld",sum1); return 0; }

#### Execution:

Input: 90 67 Output: ENTER THE 2 NO'S : BINARY OF 1ST NUM : 101101 BINARY OF 2nd NUM : 111111

#### Result:

Thus the Program for Binary Multiplication was executed Successfully.