Python to Extract Zip Files with Full Source Code

This script takes a zip file as input and extracts its content into a separate folder. The folder is named same as the input zip file and is saved in the current directory

How to use?

Just type the following in the command prompt:

python -l
Code language: CSS (css)


python -l
Code language: CSS (css)

Source Code:

import os
import zipfile
import sys
import argparse

# Code to add the cli
parser = argparse.ArgumentParser()
parser.add_argument("-l", "--zippedfile", required=True, help="Zipped file")
args = vars(parser.parse_args())

#Catching the user defined zip file
zip_file = args['zippedfile']

file_name = zip_file

#To check if the entered zip file is present in the directory
if os.path.exists(zip_file) == False:
    sys.exit("No such file present in the directory")

#Function to extract the zip file
def extract(zip_file):
    file_name = zip_file.split(".zip")[0]
    if zip_file.endswith(".zip"):
        #Will use this to save the unzipped file in the current directory
        current_working_directory = os.getcwd()
        new_directory = current_working_directory + "/" + file_name
        #Logic to unzip the file
        with zipfile.ZipFile(zip_file, 'r') as zip_object:
        print("Extracted successfully!!!")
        print("Not a zip file")


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