Python to Download Images From URL with Full Source Code

Scrap images from URL

  1. Dowmload Chrome Drive From Chrome.
  2. Run scrap-img.py fille
py scrap-img.py
Code language: CSS (css)

Requirements:

  • selenium==3.141.0

Run the Code:

Enter Path : E:\webscraping\chromedriver_win32\chromedriver.exe Enter URL : https://dribbble.com/
Code language: JavaScript (javascript)

Source Code:

from selenium import webdriver
import requests as rq
import os
from bs4 import BeautifulSoup
import time

# path= E:\web scraping\chromedriver_win32\chromedriver.exe
path = input("Enter Path : ")

url = input("Enter URL : ")

output = "output"


def get_url(path, url):
    driver = webdriver.Chrome(executable_path=r"{}".format(path))
    driver.get(url)
    print("loading.....")
    res = driver.execute_script("return document.documentElement.outerHTML")

    return res


def get_img_links(res):
    soup = BeautifulSoup(res, "lxml")
    imglinks = soup.find_all("img", src=True)
    return imglinks


def download_img(img_link, index):
    try:
        extensions = [".jpeg", ".jpg", ".png", ".gif"]
        extension = ".jpg"
        for exe in extensions:
            if img_link.find(exe) > 0:
                extension = exe
                break

        img_data = rq.get(img_link).content
        with open(output + "\\" + str(index + 1) + extension, "wb+") as f:
            f.write(img_data)
        
        f.close()
    except Exception:
        pass


result = get_url(path, url)
time.sleep(60)
img_links = get_img_links(result)
if not os.path.isdir(output):
    os.mkdir(output)

for index, img_link in enumerate(img_links):
    img_link = img_link["src"]
    print("Downloading...")
    if img_link:
        download_img(img_link, index)
print("Download Complete!!")

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