Python to Check Year is a Leap Year or Not with Source Code

With the help of this program, you can check whether a year is a leap year or not.

Source Code:

year = int(input("Enter a year:- ")) # Here, you take the input from the user if(((year % 4 == 0) and (year % 100 != 0)) or (year % 400 == 0)): """ if a year is a multiple of four and a multiple of 100 i.e. if it is a multiple of 400 it is not a leap year """ print("{0} is a leap year!!".format(year)) """ printing the output """ else: print("{0} is not a leap year!!".format(year))
Code language: PHP (php)

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