Python Speaking Dictionary with Full Source Code For Beginners

  • Speaking Dictionary is a Python program that allows the user to find the meaning of an English word by speaking it directly to the program (device).
  • Then, the program (device) will directly explain the definition of the word out loud.

Prerequisites:

  • pyttsx3
  • PyDictionary
  • speech recognition:
  • gTTS
  • pyaudio
pip install pyttsx3 pip install PyDictionary pip install SpeechRecognition pip install gtts pip install pyaudio

Run the Script:

python SpeakingDictionary.py
Code language: CSS (css)

Source Code:

SpeakingDictionary.py

import pyttsx3 from PyDictionary import PyDictionary import speech_recognition as spr from gtts import gTTS import os #Speaking class class Speak: def SpeakWord(self, audio): #Having initial constructor of pyttsx3 pSpeakEngine= pyttsx3.init('sapi5') pVoices= pSpeakEngine.getProperty('voices') #Speaking audio that got as parameter pSpeakEngine.setProperty('voices', pVoices[0].id) pSpeakEngine.say(audio) pSpeakEngine.runAndWait() #Create Recognizer, Microphone instance sRecog= spr.Recognizer() sMic= spr.Microphone() #Capture voice from microphone with sMic as source: print("Speak 'Hello' to initiate Speaking Dictionary!") print("----------------------------------------------") sRecog.adjust_for_ambient_noise(source, duration= .2) rAudio= sRecog.listen(source) szHello= sRecog.recognize_google(rAudio, language= 'en-US') szHello= szHello.lower() #If you said 'Hello', initialize the speaking dictionary if 'hello' in szHello: sSpeak= Speak() pDict= PyDictionary() print("Which word do you want to find? Please speak slowly.") sSpeak.SpeakWord("Which word do you want to find Please speak slowly") try: sRecog2= spr.Recognizer() sMic2= spr.Microphone() #Capture the word that the user want to find the meaning of with sMic2 as source2: sRecog2.adjust_for_ambient_noise(source2, duration= .2) rAudio2= sRecog2.listen(source2) szInput= sRecog2.recognize_google(rAudio2, language= 'en-US') try: #Make sure that the recognizer got the correct word print("Did you said "+ szInput+ "? Please answer with yes or no.") sSpeak.SpeakWord("Did you said "+ szInput+ "Please answer with yes or no") sRecog2.adjust_for_ambient_noise(source2, duration= .2) rAudioYN= sRecog2.listen(source2) szYN= sRecog2.recognize_google(rAudioYN) szYN= szYN.lower() #If the user said 'yes' (When the recognizer got the correct word) if 'yes' in szYN: szMeaning= pDict.meaning(szInput) print("The meaning is ", end="") for i in szMeaning: print(szMeaning[i]) sSpeak.SpeakWord("The meaning is"+ str(szMeaning[i])) #When the recognizer got the wrong word else: sSpeak.SpeakWord("I am sorry Please try again") #When the recognizer couldn't understand the answer(yes or no) except spr.UnknownValueError: sSpeak.SpeakWord("Unable to understand the input Please try again") except spr.RequestError as e: sSpeak.SpeakWord("Unable to provide required output") #When the recognizer couldn't understand the word except spr.UnknownValueError: sSpeak.SpeakWord("Unable to understand the input Please try again") except spr.RequestError as e: sSpeak.SpeakWord("Unable to provide required output")

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