CPP Program Divisors of a Factorial – Number Theory

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Given a number, find the total number of divisors of the factorial of the number. Since the answer can be very large, print the answer modulo 10^9+7.

Input format:

The first line contains T, the number of test cases.
T lines follow each containing the number N.

Output format:

Print T lines of output each containing the answer.

Constraints:

1 <= T <= 500
0 <= N <= 50000

Sample Input:

3
2
3
4

Sample Output:

2
4
8

Code:

#include <iostream>
#include <math.h>
#define m 1000000007
#define ll long long int
using namespace std;
void makeSieve(ll n)
{
    bool *isprime = new bool[n + 1];
    for (ll i = 0; i < n + 1; i++)
    {
        isprime[i] = true;
    }
    isprime[0] = false;
    isprime[1] = false;
    for (ll i = 2; i <= sqrt(n); i++)
    {
        if (isprime[i])
            for (ll j = i; j * i <= n; j++)
            {
                isprime[j * i] = false;
            }
    }
    ll total_divisors = 1;
    for (ll i = 0; i < n + 1; i++)
    {
        if (isprime[i])
        {
            ll current_sum = 0;
            for (ll j = 1; pow(i, j) <= n; j++)
            {
                current_sum += n / pow(i, j);
            }
            total_divisors =(total_divisors%m * (current_sum + 1)%m)%m;
        }
    }
    cout << total_divisors << endl;
    delete[] isprime;
}
int main()
{
    ll t;
    cin >> t;
    while (t--)
    {
        ll n;
        cin >> n;
        makeSieve(n);
    }
}
Code language: C++ (cpp)

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